Math, asked by sumukhnayak2005, 8 months ago

The LCM of (x+y)² , (x-y)² and (x²-y²) is​

Answers

Answered by narapogusudhakar777
2

Step-by-step explanation:

2 x² - 18 y² = 2 (x² - 9 y²)

= 2 (x² - (3 y)²)

= 2 (x + 3y) (x - 3y)

5 x² y + 15 x y² = 5 x y (x + 3 y)

x³ + 27 y³ = x³ + (3 y)³

= (x + 3 y) (x² + x (3y) + (3y)²)

= (x + 3 y) (x² + 3 x y + 9 y²)

L.C.M = 2 (x + 3y) x 5 x y x (x² + 3 x y + 9 y²)

= 10 x y (x + 3y) (x² + 3 x y + 9 y²)

Similar questions