Question

The LCM of x²-1,x²-4x+3 and X²+3x+2 is
A)(x+3) (x+1)
B)(x²-1) (x+2) (x-3)
C)(x-1) (x-2) (x-3)
D)(x²-1) (x+2) (x+3)​

Answer 1

Answer:

Step-by-step explanation:

Factors of ( x² - 1 ) = ( x - 1 ) ( x + 1 )

Factors of ( x² - 4x + 3 ) = x²-3x - x + 3 = x (x - 3 ) - 1 (x - 3)= ( x - 1 ) ( x - 3 )

Factors of ( x²+ 3x + 2 ) = x²+2x +x +2 = x(x +2)+ 1 (x +2)= (x + 1) (x +2)

∴The L.C.M.= (x -1) (x +1) (x +2) (x -3)

= ( x²- 1) ( x +2) (x -3)

Hence, option ( B ) is correct.