Question

The least count of a stop watch is 0.2s .The time of oscillations of a pendulum is measured to 25s. Find the percentage error in time period .

Answer 1

Explanation:

$percentage \: error = (25 \div 25.2) \times 100 \\ \: \: \: \: \: \: = 99.2percent$

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Answer 2

Answer:

Percentage error

=minimum readings /actual reading

=0.2/25

=0.008

=0.8 %