Question

The least integer k which makes the roots of the equation x²+5x+k=0 imaginary is​

Answer 1

Answer:

If the zero is imaginary then b^2- 4ac < 0

a =1, b=5, c=k

5^2 - 4 (1)(k) < 0

25-4k < 0

25 < 4k

25/4 < k

The least integer k should be less than 25/4

Hope this helps u

Answer 2

$\huge \mathfrak \red{answer}$

formula..

$\bf{ \huge \boxed{ \red{ \tt{a {x}^{2} + bx + c = 0 \: }}}}$

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$\sf{ {2}^{2} + 5x + x = 0}$

[a=1 , b=5 , c=k]

$\sf{ {5}^{2} - 4(1)(k) < 0}$

$\sf{25 < 4k}$

$\sf{k > \frac{25}{4} > 6.25}$

$\sf \red{k = 7}$