the least integral value in range of f(x) = 3^x + 3^-x is
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the answer -3 hop it helps
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Answer:
The least integral value is 2.
Step-by-step explanation:
Given: f(x) =
Recall: If two positive values a and b are given, then
AM of a and b ≥ GM of a and b
Here a= 3ˣ and b= 3⁻ˣ
Where 3ˣ >0 and 3⁻ˣ > 0 so we can apply AM and GM concept here.
=> AM of 3ˣ and 3⁻ˣ = (3ˣ + 3⁻ˣ)/2
=> GM of 3ˣ and 3⁻ˣ = √(3ˣ × 3⁻ˣ) = 1
∵ AM ≥ GM
∴ (3ˣ + 3⁻ˣ)/2 ≥ 1
⇒ 3ˣ + 3⁻ˣ ≥ 2
Hence, the range of the function f(x) = 3ˣ + 3⁻ˣ is [2 , ∞) i.e; least integral value is 2.
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