Question

The least number of five digits which when divided by 16, 24, 30 and 32 leaves a remainder 2 in each case is
please answer

Answer 1

We know,

• 16 = 2 × 2 × 2 × 2

• 24 = 2 × 2 × 2 × 3

• 30 = 2 × 3 × 5

• 32 = 2 × 2 × 2 × 2 × 2

LCM = 2 × 2 × 2 × 3 × 4 × 5 = 480   (3 digits number)

Largest number of 5 digits = 99999

99999 ÷ 480 = 208.33125

Thus ,

Possible largest 5 digits number = 480 × 208 = 99840

Required largest 5 digits number = 99840 + 10

Required largest 5 digits number = 99850