Question

The least number such that, when it divided by 15, 25, 35 and 45, leaves a reminder 7, 17, 27 and 37 respectively, is​

Answer 1

Answer:

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Step-by-step explanation:

Divisors are 15 , 25 , 35 and 45

Respective Remainders: 7 , 17 , 27 , 37

To find: Least Number divided by given divisors and leaves respective remainders.

15 - 7 = 8

25 - 17 = 8

35 - 27 = 8

45 - 37 = 8

Since, Difference between Divisors and remainders is 8 in each case.

So, we have to find LCM of the divisors and subtract 8 from them.

Using Prime factorization method,

15 = 3 × 5

25 = 5 × 5

35 = 5 × 7

45 = 3 × 3 × 5

LCM = 5 × 3 × 3 × 7 × 5 = 1575

Answer 2

Answer:

So first we need to find LCM of (15-7), (25-17), (35-27) and (45-37).

LCM of - 8, 8, 8 and 8 = 64 is your answer.

Hope it helps...