Question

The least number which when divided by 10, 12 and 15 leaves remainder 3 in each case is: ​

Answer 1

Answer:

123

Step-by-step explanation:

First of all,

We have to find the LCM:-

Prime Factorization of 10 = 2×5

Prime Factorization of 12 = 2×2×3

Prime Factorization of 15 = 3×5

LCM = 2×5×2×2×3

LCM = 120

Now,

We have to add the remainder to the LCM.

Required Number = 120+3

= 123

Therefore, the least number which when divided by 10, 12 and 15 leaves remainder 3 in each case is 123.