Question

the least number which when divided by 15,27, 35 and 42 leaves in each case a remainder 7 is:

Answer 1

I think it is 135
135 is the answer

Answer 2

Answer:

1897

Step-by-step explanation:

In this type of question,

15, 27, 35, and 42

Take L.C.M  of 15, 27, 35, and 42 by prime factorization method,

15 = 3 * 5

27 = 3 * 3 * 3

35 = 5 * 7

42 = 2 * 3 * 7

L.C.M = 3 * 3 * 3 * 2 * 5 * 7 = 1890

1890 will be exactly divisible by 15, 27, 35, and 42

So, the number which leaves remainder 7 is 1890 + 7 = 1897