the least number which when divided by 15,27, 35 and 42 leaves in each case a remainder 7 is:
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Answered by
3
I think it is 135
135 is the answer
135 is the answer
Answered by
6
Answer:
1897
Step-by-step explanation:
In this type of question,
15, 27, 35, and 42
Take L.C.M of 15, 27, 35, and 42 by prime factorization method,
15 = 3 * 5
27 = 3 * 3 * 3
35 = 5 * 7
42 = 2 * 3 * 7
L.C.M = 3 * 3 * 3 * 2 * 5 * 7 = 1890
1890 will be exactly divisible by 15, 27, 35, and 42
So, the number which leaves remainder 7 is 1890 + 7 = 1897
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