Question

The least number which, when divided by 16, 18, 20, and 25 leaves 4 as remainder in each case but when divided by 7 leaves no remainder is?​

Answer 1

The L.C.M of 16,20,25,18 is to be 3600.

The required number will be in form of 3600x+4.

Now apply hit and trial method to find the least value of x for which 3600x+4 are divisible by 7.

By putting x = 1, 2, 3 and putting the value of x = 5, the required number comes to be 18004