The least number which when increased by 1 is divisible by12,18,24,32 is
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0
It can be 2.
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Answered by
1
Answer:
187
Step-by-step explanation:
Prime factors of 12,18,24,32 are
12=2*2*3
18=2*3*3
24=2*2*2*3
32=2*2*2*2*2
So LCM( 12,18,24,32)=2^5*3^2=32*9=288
so 288 is the least no divisible by 12,18,24,32
Number is divisible by 12,18,24,32 after increasing 1
so the the final number
=188-1
=187
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