the least of five consecutive odd number is 2n-1 what is the greatest number
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Answered by
38
Hey MATE!!!
Since thr smallest number of the given set of odd numbers is (2n-1) therefore the given progression must proceed in the following way :
2n-1 , 2n +1, 2n+3, 2n+5, 2n+7
Hence the greatest of the 5 odd numbers is => 2n +7
Hope it helps
HAKUNA MATATA :))
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13
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Hey mate your answer is here
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