Question

the least two digits in X=∑k

Answer 1

the least two digits in X=∑k

X = 1!+2!+3!+4!+5!+6!+7!+8!+9!+10!+……..X = 1+2+6+24+120+720+5040+40320+362780+3627800+……..After 10!, we will have 00 as the last two digit for all the factorials.Therefore, we will add the last two digits of 1 to 9 factorials.Hence, the answer is 13

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