Question

The least value of 'n' for which the sum of the first n-odd natural numbers
exceeds 5.000 is:​

Answer 1

Answer:

n odd numbers

1,3,5,7,9

Sum >5000

We will first find n for Sum = 5000

Sn = n/2(2a+(n-1)d)

a=1,d=2,Sn =5000

5000= n/2(2*1+(n-1)*2)

10000=n+(n-1)*2

10000=n+2n-2

10002=3n

n=3334

so for n =3334 Sum = 5000

SO for n=3335 Sum >5000