Question

The least value of'n'such that 1+3+5+7..............N terms >500is

Answer 1

heya!!!!

Sn>500

so,

n/2{2×1+(n-1)2}>500

n/2{2+2n-2}>500

n(2n)>1000

2n²>1000

n²>500

n>√500

n>22.36(approx)

therefore n=23

thanks!!

mark as brainliest

follow me

Answer 2

Answer:

Step-by-step explanation:

1 + 3 + 5 + 7 + ........ + (2n - 1) = n^2

n^2 > 500

n > sqrt(500) = 10sqrt(5).

the least value of n is [ 10sqrt(5) ] + 1, where [ ] denotes the integer part.

the least value of n is therefore 23.