Math, asked by dhrutialways, 4 months ago

the least value that should be subtracted from 4x^4 - 2^3 - 6x^2 + x - 5,so that the result is exactly divisible by 2x^2 + x - 1 is?

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Answered by Anonymous
0

Answer:

3m+6n-5d , B equal to 9m-2d+19n and C equal to 17d-12m+20n ,then find the value of A+B+C(2-A) / B-A​

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3m+6n-5d , B equal to 9m-2d+19n and C equal to 17d-12m+20n ,then find the value of A+B+C(2-A) / B-A​

Your answer

(quit)

BrainlyThebestManGenius

BrainlyThebestManGenius

Step-by-step explanation:

Answered by hp5217885
2

Lets divide (4x4 - 2x3 - 6x2 + x - 5) by (2x2 + x – 1) as shown. Hence (−6) should be subtracted from (4x4 − 2x3 − 6x2 + x − 5) so that the resulting polynomial is exactly divisible by (2x2 + x – 1).

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