Question

The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (HOOCCOOH) and must be removed before the stems are used to make rhubarb pie. If pKa1 = 1.23 and pKa2 = 4.19, what is the pH of a 0.0200 M solution of oxalic acid?

Answer 1

Answer:Concentrati on of H2C20.0247 M ICE table constructedis as follows HHC(aq) + H,o'(aq) I(M)00247 C(M) x E (M) (00247-x) 1st acidionizati on constant, Kal =_THAO4 10-pr-10-123-5.9810-2- (00247-x x0.0187 From the equilibrium table, [H3ợJ-x:0 0187M [HC204-]-x=0.0187M ICE table constructed for the2 onization of H2C0 is as follows HCO,-(aq) + H20(1) 992-(aq) + H,0+(aq) 0,042-(aq) H,0+ (aq I(M): 0.0187 C(M): -x E (M): (0.0187-x) 0.0187 0.0187+x 2"d acidionization constant, K2 10-p":10-4."-6 4x10% (0.0187 +x)(x) 0.0187- x x= 6.4×10-5 From the equilibrium table. [H(0.0187+x)M =(0.0187+6.4×10-5 0.0187 M pH-l0g[H,0log (0.0187) 1.73

Explanation:

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