Math, asked by hdrc7936, 7 months ago

The leght of a swimming pool in virac resort is 8 m longer than its width and the area is 105m².

Answers

Answered by wargranite
1

Step-by-step explanation:

area=105m²

l=8+w

find width

l×b=105

(8+w)×w=105

8w+w²-105=0

w²+8w-105=0

w²+15w-7w-105=0

w(w+15)-7(w+15) =0

w-7=0 ,w+15=0

w=7 m as lenght cannot be negative

L=15m

Answered by gurunavu
3

Answer:

The Length of a swimming pool is 8m longer than its width and the area is 105m2. don't solve it write the problem in a mathematical sentence

:

Let x = width

then

(x+8) = the length

the area, length * width

x(x+8) = 105

x^2 + 8x - 105 = 0, a quadratic

its \: a \:  example}

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