Math, asked by haddff, 1 year ago

the legs of the right angled triangle are in ratio 4:3 and its area is 4056cm square find the length of each leg

Answers

Answered by gaurav2013c
13
Let the Base and perpendicular be 4a and 3a respectively

Area = 1 /2 [ 4a × 3a]

=> 4056 = 1/2 ( 12 a^2)

=> 6a^2 = 4056

=> a^2 = 676

=> a = 26 cm


Base = 26 × 4 = 104 cm

Perpendicular = 26 × 3 = 78 cm

haddff: how it came 26cm
gaurav2013c: square root of 676 is 26
haddff: thanks
Answered by Anonymous
18
hay!!

Dear-

According to the question let the perpendicular and base be 3a and 4a

Area=> 1/2(4a×3a)

=> 4056=1/2(12a²)

=> 4056=6a²

=> 676=a²

=> 26=a

Then, base =>26×4=104

Perpendicular => 26×3=78

I hope it's help you
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