The legth of a pendulum is (1.5+_0.01)m and the acceleration due to gravity is taken into account as (9.8+_0.1)ms_2.calculate the time period of the pendulum with uncertainty in it
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∣
∣
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∣
3
1+α+β
1+α
2
+β
2
1+α+β
1+α
2
+β
2
1+α
3
+β
3
1+α
2
+β
2
1+α
3
+β
3
1+α
4
+β
4
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=
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∣
∣
∣
1
1
1
1
α
α
2
1
β
β
2
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
1
1
1
1
α
β
1
α
2
β
2
∣
∣
∣
∣
∣
∣
∣
∣
=
∣
∣
∣
∣
∣
∣
∣
∣
1
1
1
0
α−1
α
2
−1
0
β−1
β
2
−1
∣
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∣
∣
∣
2
=((α−1)(β
2
−1)−(β−1)(α
2
−1))
2
=(α−1)
2
(β−1)
2
(α−β)
2
⇒k=1
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