Question

the lenght of a rectangle is two times its width the perimeter of the rectangle is 180cm find the dimension of the rectangle​

Answer 1

Step-by-step explanation:

plz refer to the attachment above

Answer 2

Answer:

$\boxed{\sf Length \ of \ the \ rectangle = 60 \ cm}$

$\boxed{\sf Width \ of \ the \ rectangle = 30 \ cm}$

Given:

Length of the rectangle = Twice Width of the rectangle

Perimeter of the rectangle = 180 cm

To Find:

Dimensions of the rectangle i.e. Length & Width of the rectangle

Step-by-step explanation:

Let width of the rectangle be 'w'

So,

Length of the rectangle = 2w

$\sf \implies Perimeter \: of \: the \: rectangle =2( Length + Width) \\ \\ \sf \implies 180 =2 (2w + w) \\ \\ \sf \implies 180 = 2(3w) \\ \\ \sf \implies 180 = 6w \\ \\ \sf \implies 6w = 180 \\ \\ \sf \implies w = \frac{180}{6} \\ \\ \sf \implies w = 30$

$\therefore \\ \sf Width \ of \ the \ rectangle = 30 \ cm \\ \sf Length \ of \ the \ rectangle = 2w \\ \sf = 2 \times 30 \\ \sf = 60 \ cm$