the lenght of the longest rod that can be placed in a room of dimenssions 10 m×10m×5m is
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length of the room= 10m
breadth of the room = 10m
height of the room = 5m
the length of the longest rod that can be placed= length of the diagonal
=√(l²+b²+h²)
=√(10²+10²+5²)
=√(100+100+25)
=√(225)
=15m
breadth of the room = 10m
height of the room = 5m
the length of the longest rod that can be placed= length of the diagonal
=√(l²+b²+h²)
=√(10²+10²+5²)
=√(100+100+25)
=√(225)
=15m
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