the lenght of the minute hand of a clock is 14cm .find the area swept by the minute hand in 5
minutes
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Answered by
8
r=14cm
theeta=3
area swept by minute hand =area of sector
=theeta/360×22/7×14×14
=30/360×22/7×14×14
=1/12×22×28
=1/3×11×14
=154/3cm²
theeta=3
area swept by minute hand =area of sector
=theeta/360×22/7×14×14
=30/360×22/7×14×14
=1/12×22×28
=1/3×11×14
=154/3cm²
Answered by
5
Total angle of circle= 360*
Min in one hour= 60
So angle in 1 min= 360/60=6*
So angle in 5 min = 6* 5= 30*
Area of sector= theta/360 * pie r ^2
= 30/360 * 22/7 * 14 *14
=154/3 cm^2
Min in one hour= 60
So angle in 1 min= 360/60=6*
So angle in 5 min = 6* 5= 30*
Area of sector= theta/360 * pie r ^2
= 30/360 * 22/7 * 14 *14
=154/3 cm^2
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