the lenghts of two sides of a right angled triangle containing the right angle differ by 2 cm. if the area of the triangle is 24 cm2, find the perimeter of the triangle
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❌❌✴HOLLA✴❌❌
➖❓❓QUESTION❓❓➖:-
the lenghts of two sides of a right angled triangle containing the right angle differ by 2 cm. if the area of the triangle is 24 cm2, find the perimeter of the triangle
➖➖➖YOUR ANSWER➖➖➖ :-
Let one side be = x i.e base
then other side will be y i.e height
Their difference is 2
x - y = 2
y = x - 2.....
Area = ½ × b × h = 24
½ × x × ( x - 2 ) = 24
x² - 2x - 48 = 0
x² - 8x + 6x - 48 = 0
x × ( x - 8 ) + 6 × ( x - 8 ) = 0
( x + 6 ) × ( x - 8 ) = 0
x = - 6 or 8 cm
side cannot be in negative.... so x = 8 cm
y = x - 2 = 6 cm
Hypotenuse = √ ( 8² + 6² )
= √ ( 100 )
= 10 cm
So perimeter is.....
Perimeter = x + y + hypotenuse
= 8 + 6 + 10
= 24 cm......
❎❎@RRJACK❎❎
♊♊HOPE IT HELPS YOU♊♊
➖❓❓QUESTION❓❓➖:-
the lenghts of two sides of a right angled triangle containing the right angle differ by 2 cm. if the area of the triangle is 24 cm2, find the perimeter of the triangle
➖➖➖YOUR ANSWER➖➖➖ :-
Let one side be = x i.e base
then other side will be y i.e height
Their difference is 2
x - y = 2
y = x - 2.....
Area = ½ × b × h = 24
½ × x × ( x - 2 ) = 24
x² - 2x - 48 = 0
x² - 8x + 6x - 48 = 0
x × ( x - 8 ) + 6 × ( x - 8 ) = 0
( x + 6 ) × ( x - 8 ) = 0
x = - 6 or 8 cm
side cannot be in negative.... so x = 8 cm
y = x - 2 = 6 cm
Hypotenuse = √ ( 8² + 6² )
= √ ( 100 )
= 10 cm
So perimeter is.....
Perimeter = x + y + hypotenuse
= 8 + 6 + 10
= 24 cm......
❎❎@RRJACK❎❎
♊♊HOPE IT HELPS YOU♊♊
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