the length and breadth of a garden are in the ratio 2 : 1. a path and its perimeter is 240 m. a path of 2 m wide runs inside the garden along the boundary. find the area of the path
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let the length and breadth of the park be 2x and x respectively.
Perimeter of the park = 240 m
2(2x+x) = 240
6x = 240
x = 40
So, length = 2×40 = 80 m
breadth = 40 m.
area of park = l×b = 80m×40m = 3200 m^2
Width of path = 2m
So, inner length = 80m -(2+2)m = 76m
inner breadth = 40 m -(2+2) = 36 m
area of inner part = inner l × inner b
= 76m × 36m = 2736 m^2
ar. of path = ar. of park - area of inner park
= (3200-2736) m^2 = 464 m^2
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