Question

the length and breadth of a lawn are in the ratio 2 is to 1 and its area is 280 m square there is a path of width 1 m running inside the lawn along its boundary find the area of the path

Answer 1

Answer:

Step-by-step explanation:

let length = 2x

then breadth = 1x

perimeter =240m

so, 2 (2x+1x)= 240m

4x+2x=240m

so,6x=240m means x= 240/6=40m

then length = 2×40=80m

breadth = 1×40=40m

area of outer park = 80×40 = 3200sq.m

area of inner park = 80-4×40-4= 76×36

= 2736sq.m

area of path = outer park-inner park

= 3200sq.m - 2736sq.m

=464sq.m

cost of paving the path = 464×80 =Rs.37120

Answer 2

Answer:

Step-by-step explanation:

let length = 2x

then breadth = 1x

perimeter =240m

so, 2 (2x+1x)= 240m

4x+2x=240m

so,6x=240m means x= 240/6=40m

then length = 2×40=80m

breadth = 1×40=40m

area of outer park = 80×40 = 3200sq.m

area of inner park = 80-4×40-4= 76×36

= 2736sq.m

area of path = outer park-inner park

= 3200sq.m - 2736sq.m

=464sq.m

cost of paving the path = 464×80 =Rs.37120