Question

The length and breadth of a park is in the ratio 2:1,its perimeter is 240 m.A path of 2m wide runs inside it along boundary.Find the cost of paving the path 3 rupees per m²​

Answer 1

Answer:

1392 rupees

Step-by-step explanation:

Call the breadth B and the length L.

Ratio L : B = 2 : 1  =>  L = 2B.

Perimeter = 240 m  =>  2 ( B + L ) = 240 m  =>  6B = 240 m  =>  B = 40 m.

So the breadth is B = 40 m and the length is L = 80 m.

Since the path is 2 m wide, the rectangle inside the path has breadth = 40 - 4 = 36 m and length = 80 - 4 = 76 m  ( "- 4" since the path takes 2 m from each of the four sides).

Area of path

= area of park - area inside path

= 40 × 80 m²  -  36 × 76 m²

= 3200 m² - 2736 m²

= 464 m².

Cost of paving

= area of park × cost per m²

= 464 × 3 rupees

= 1392 rupees