the sum of the squares of two consecutive even natural numbers is 100 . find the numbers
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Answered by
2
8 and 6
= 8sq. + 6sq.
=64 + 36
= 100
= 8sq. + 6sq.
=64 + 36
= 100
Answered by
10
let n be a number. Let n+2 be the other number. Then:
n²+(n+2)²=100
n²+n²+4n+4=100
2n²+4n+4=100
n²+2n+2=50
n²+2n-48=0
(n-6)(n-8)=0
(n-6)=0 or (n-8)=0
n=6 or n=8
When n=6 then n+2= 8 and we get 6²+8²=36+64=100.
When n=8 then n+2=10 and we get 8²+10²=64+100=164.
Clearly n=6 and n+2=8 is correct.
The 2 consecutive even numbers whose squares add up to 100 is 6 and 8.
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