Question

the length and breadth of a rectangle are 18 m and 12m respectively. If its perimeter is equal to perimeter of another square, find the side of the square.

Answer 1

hey friend

here is your answer

given that perimeter of rectangle = perimeter of square .........(1)

perimeter of a rectangle = 2( l + b )

l = 18m , b = 12m

perimeter of rectangle = 2( 18 + 12 )

=> 2 * 30 = 60m

but from equation (1)

perimeter of a square = 60m

4s = 60

=> s = 60/4 = 15m

side of the square = 15m

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Answer 2

$\underline{\textbf{Hey Mate Here Is Your Answer}}$

$\underline{\textbf{Given That...}}$

The Length Of A Rectangle Is Equal To 18m And Breadth Equal To 12m And It's Also Given That The Perimeter

Of This Rectangle Is Equal To Perimeter Of A A Square Now We Need To Find The Side Of The Square ..

Now Let's Move For Solution...

$\underline{\textbf{Solution..}}$

As Per The Question

$\textbf{Length Of Rectangle = 18m}$

$\textbf{Breadth Of Rectangle = 12m}$

Now According To Question It's Said That..

$\textbf{Perimeter Of Rectangle = Perimeter Of Square }$

Now We Know That

$\boxed{\textbf{Perimeter Of Rectangle = 2 ( L + B ) }}$

Where L = 18m And Breadth = 12m

Therefore Perimeter =

$\textbf{Perimeter Of Rectangle = 2 ( 18m+ 12m ) }$

That Is

$\mathbf{Perimeter \:=\: 30 \:\times \:2\: = \:60m}$

So Now We Have

$\boxed{\textbf{Perimeter Of Rectangle = 60m }}$

Now As Per The Question It's Said That The Perimeter Of Rectangle = Perimeter Of Square

Now We Know That

$\boxed{\textbf{Perimeter of Square = 4s }}$

Where S = length of Side

Therefore ..

$\mathbf{Perimeter \: Of \: Square\: = \:4s\: = \: 60m}$

Now Taking 4 To RHS We Have ➡️

$\mathbf{ S= \frac{60m}{4}}$

So Now We have

$\textbf{ S = 15m }$

Therefore

$\textbf{The Side Of Square = 10m}$

$\underline{\textbf{Hence The Required Answer is }}$

$\boxed{\boxed{\textbf{Side = 15m}}}$

$\large{\bold{Thanks..}}$