Question

The length and breadth of a rectangle are 5.7 plus minus 0.1 cm and 3.4 plus minus 0.2 cm calculate area of the rectangle with error limits

Answer 1

$\Large{\underline{\underline{\mathfrak{\bf{Question}}}}}$

The length and breadth of a rectangle are ( 5.7 ± 0.1 ) cm and ( 3.4 ± 0.2 ) cm calculate area of the rectangle .

$\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$

$\Large{\underline{\mathfrak{\bf{\blue{Given}}}}}$

• Length = (5.7 ± 0.1)
• Breadth = ( 3.4 ± 0.2)

$\Large{\underline{\mathfrak{\bf{\blue{Find}}}}}$

• Area of rectangle

$\Large{\underline{\underline{\mathfrak{\bf{Explanation}}}}}$

First, For (+ ve ) sign

Then,

• Length = 5.7 + 0.1 = 5.8
• Breadth = 3.4 + 0.2 = 3.6

$\small\red{\boxed{\sf{\blue{\:Area_{Rectangle}\:=\:(Length)\times (Breadth)}}}} \\ \\ \mapsto\sf{\:Area_{Rectangle}\:=\:(5.8)\times (3.6)} \\ \\ \mapsto\sf{\orange{\:Area_{Rectangle}\:=\:20.88\:cm^2\:\:\:\:\:\:Ans}}$

Second, For ( -ve ) Sign,

Then,

• Length = 5.7 - 0.1 = 5.6
• Breadth = 3.4 - 0.2 = 3.2

$\small\red{\boxed{\sf{\blue{\:Area_{Rectangle}\:=\:(Length)\times (Breadth)}}}} \\ \\ \mapsto\sf{\:Area_{Rectangle}\:=\:(5.6)\times (3.2)} \\ \\ \mapsto\sf{\orange{\:Area_{Rectangle}\:=\:17.92\:cm^2\:\:\:\:\:\:Ans}}$

Thus:-

When,

• Length = 5.8
• breadth = 3.6

$\mapsto\sf{\green{\:Area_{Rectangle}\:=\:20.88\:cm^2}}$

When,

• Length = 5.6
• breadth = 3.2

$\mapsto\sf{\green{\:Area_{Rectangle}\:=\:17.92\:cm^2}}$

Answer 2

Answer:

17.92 cm² is answer of question