The length and breadth of a rectangular field are 38 m and 32 m . A path of uniform width exists within the field along the boundary. If the area of the path is 600 sq.m , then find the width of the path
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let the width of the path is x m
then,without path length and breadth are
(38-2x) m and (32-2x) m
so ,
38×32-(38-2x)(32-2x)=600
=> 38×32-(38×32-64x-76x+4x^2=600
=> 38×32-38×32+64x+76x-4x^2=600
=> 140x-4x^2-600=0
=> -4(x^2-35x+150)=0
=> x^2-35x+150=0
=> x^2-30x-5x+150=0
=> x(x-30)-5(x-30)=0
=> (x-30)(x-5)=0
=> x-30=0
=> x=30
x-5=0
=> x=5
x is not equal to 30 because width of the path is not 30 m as breadth is 32 m
so width of the path is 5 m
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