the length and breadth of a rectangular field are in the ratio 3:2ifthe area of thefild is 294m²find the cost of fencingthe field at ₹ 4.50 per metre?
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area of recrangle = l x b = 294 m^2
let length be, 3x. ... breadth, 2x
3x*2x= 6x^2 = 294
x^2= 49
x= 7
thus, length = 3*7 = 21
breadth = 2*7 = 14
circumference = 2(l+b) = 2(21+14) = 2*35 = 70
total cost = 70 * 4.50 = 315 rs
let length be, 3x. ... breadth, 2x
3x*2x= 6x^2 = 294
x^2= 49
x= 7
thus, length = 3*7 = 21
breadth = 2*7 = 14
circumference = 2(l+b) = 2(21+14) = 2*35 = 70
total cost = 70 * 4.50 = 315 rs
ankit199:
thanks
Answered by
0
Let the length and breadth are 3x and2x respectively , then-
Area = Length * Breadth
294 sq.m = 3x * 2x
6x^2 = 294 sq.m
x^2 = 49 sq.m
x=7m
=> Length = 3x = 21m Breadth = 2x = 14m
Perimeter of field = 2(l+b) = 2(21+14) = 70 m
Cost of fencing=Rs. 4.50*70 = Rs.315
Area = Length * Breadth
294 sq.m = 3x * 2x
6x^2 = 294 sq.m
x^2 = 49 sq.m
x=7m
=> Length = 3x = 21m Breadth = 2x = 14m
Perimeter of field = 2(l+b) = 2(21+14) = 70 m
Cost of fencing=Rs. 4.50*70 = Rs.315
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