Math, asked by SabGadheHain, 2 months ago

The length and breadth of a rectangular field is 60m and 30m respectively If a student runs around the field 5 times find the total distance he ran​

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Answered by pratyushara987
12

Answer:

hope it helps you

refer to attachment

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Answered by llXxMrSubanshxXll
670

 \red{\bigstar \large\underline{\boxed{\bf\pink{Answer:-}}}}

DIAGRAM :

\begin{gathered} \blue{\begin{gathered} \sf{60\:m}\huge\boxed{ \begin{array}{c c} \: \: \: \: \: \: \\ \: \:  \: \: \:  \:  \:  \: \\ \:  \:   \:  \:  \:\:\:\:\:\:\:\:\:\:  \:  \:  \ \: \:  \: \  \: \: \: \: \: \end{array}} \\ \: \: \: \: \: \sf{30 \: m} \end{gathered}}\end{gathered}

 \red{ \sf \bigstar  Concept}

Here , we have given the length and breadth of field Length = 70 m and Breadth = 30 mm. A student runs around the field 5 times . So we have to calculate the total distance he covered . First we have to find it's perimeter by using Formula 2(L + b) where L = length and B = Braedth . Then we will multiply the perimeter of the field with 5 as he covers 5 rounds.

  \large\sf \green{ \underline{Given:-  }}

  • Length of field = 60 mm
  • Breadth of field = 30 m

 \large \pink{\sf{ \underline{Solution:- }}}

We know that

{\boxed{\sf  \orange{Perimeter \tiny(Rectangle) }}}  \\  \sf \red{=2(l + b)}

 \sf \blue{ \mapsto2(60 + 30) \: m}

 \sf \green{ \mapsto2(90)m} \\  \sf \orange{ \mapsto180 \: m}

Therefore , perimeter of field = 180 cm

Means the distance covered by him in 1 round = 180

The distance covered by him in 5 rounds =

 \sf \color{yellow} \mapsto5 \times 180

 { \boxed {\sf \color{aqua}{ \mapsto900 \: m}}}

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