the length and breadth of a rectangular Garden are in the ratio 7 :3. If the area of the field is 525 square m, then find the cost of fencing is at rs.75 per m
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Given the length and breadth of a rectangular garden is 7:3.
Let the length be 7x. --- (1)
Let the breadth be 3x. --- (2)
Given Area of the field = 525 sq.m
We know that Area = l * b
525 = 7x * 3x
525 = 21x^2
525/21 = x^2
25 = x^2
x = 5m.
Substitute x = 5 in (1) and (2), we get
Length = 7 * 5 = 35m .
Breadth = 3 * 5 = 15m.
We know that perimeter of the field = 2(l+b)
= 2(35 + 15)
= 100m.
Given the rate of fencing = 75 per meter.
The cost of fencing = 75 * 100
= 7500m.
Hope this helps!
Let the length be 7x. --- (1)
Let the breadth be 3x. --- (2)
Given Area of the field = 525 sq.m
We know that Area = l * b
525 = 7x * 3x
525 = 21x^2
525/21 = x^2
25 = x^2
x = 5m.
Substitute x = 5 in (1) and (2), we get
Length = 7 * 5 = 35m .
Breadth = 3 * 5 = 15m.
We know that perimeter of the field = 2(l+b)
= 2(35 + 15)
= 100m.
Given the rate of fencing = 75 per meter.
The cost of fencing = 75 * 100
= 7500m.
Hope this helps!
Answered by
1
let x be the required no and
let 7x be the length n 3x be the breadth
A/Q
Area of rectangular field
=> lb = 525
=> 21x^2 = 525
=> x^2 = 25
=> x = 5 m
Hence length , => 7 × 5 => 35
breadth , => 3×5 = 15
Cost = rate × perimeter
= 75 × 100 ( by perimeter)
= ₹7500
Hence the cost is ₹ 7500
hope this helps u
let 7x be the length n 3x be the breadth
A/Q
Area of rectangular field
=> lb = 525
=> 21x^2 = 525
=> x^2 = 25
=> x = 5 m
Hence length , => 7 × 5 => 35
breadth , => 3×5 = 15
Cost = rate × perimeter
= 75 × 100 ( by perimeter)
= ₹7500
Hence the cost is ₹ 7500
hope this helps u
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