the length and breadth of a rectangular Park are in the ratio 5:2. A wide path of 2.5m that runs All Around The Park has an area 445 sq.m . Find the dimensions of the park.
Answers
Answered by
28
Heya mate,Here is ur answer
Refer to the attachment☺☺
Let the common ratio be x.
So,length of the park =5x
Breadth=2 x
Area of park =l×b
=5x×2x
=10x^2
Width of road =2.5 m
So, length of road =5x+2.5+2.5
=5x+5
Breadth of road = 2x+ 2.5 +2.5
= 2x+5
Area of road = 445 m^2
445= Length of road × breadth of road - area of park
445= (5x+5)(2x+5)-10x^2
445= 10x^2 + 25 x+10x+25 -10x^2
445= 35 x +25
445-25 =35 x
420 =35 x
420/35=x
12=x
So,the dimensions of the park are :
Length= 5x
=5×12
=60 m
Breadth=2x
=2×12
=24 m
=========================
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
Refer to the attachment☺☺
Let the common ratio be x.
So,length of the park =5x
Breadth=2 x
Area of park =l×b
=5x×2x
=10x^2
Width of road =2.5 m
So, length of road =5x+2.5+2.5
=5x+5
Breadth of road = 2x+ 2.5 +2.5
= 2x+5
Area of road = 445 m^2
445= Length of road × breadth of road - area of park
445= (5x+5)(2x+5)-10x^2
445= 10x^2 + 25 x+10x+25 -10x^2
445= 35 x +25
445-25 =35 x
420 =35 x
420/35=x
12=x
So,the dimensions of the park are :
Length= 5x
=5×12
=60 m
Breadth=2x
=2×12
=24 m
=========================
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
Attachments:
Similar questions