the length and breadth of a rectangular sheet are 16 cm and 12 cm respectively.A square of maximum size is to be cut without wasting the sheet.What will be the side of such a square?
Answers
Answer:
Option A is right
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cm
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cm
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm 2
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm 2
Option A is rightperimeter of original reactangle =2×(20+10) cm=60 cmAnd Area =20 cm×10 cm=200 cm 2 Now, rectangle of length 5 cm and breadth 2 cm are removed from original rectangle.So, from figure,perimeter of new rectangle =(20+10+(20−5)+(10−2)+5+2) cm=60 cmNow, area of new rectangle =Area of original reactangle-area of cut out=200−(2×5)=200−10=190 cm 2 ∴ Perimeter remains the same but area changes.
Answer:
13.85 cm
Step-by-step explanation:
Area of rectangle = l × b sq.units = 16 × 12 = 192 cm²
Area of rectangle = Area of square
Area of square = a² sq.units
a² = 192 cm
a = 13.85 cm
Maximum size = 13.85 cm
Hope it helps you:)