The length and breadth of a rectangular wire frame are 32cm and 12cm respectively it is bent into the shape of a circle find the radius of the circle
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14
given length = 32 cm
breadth = 12 cm
therefore perimeter of the rectangle = 2(l+b) 2( 12+32) = 88 cm
therefore length of the wire is 88 cm
Therefore circumference of the circle = 88 cm
therefore
2 × 22/7 × r = 88
or, r = 88×7/22×2 = 14 cm (ans)
may it help you
breadth = 12 cm
therefore perimeter of the rectangle = 2(l+b) 2( 12+32) = 88 cm
therefore length of the wire is 88 cm
Therefore circumference of the circle = 88 cm
therefore
2 × 22/7 × r = 88
or, r = 88×7/22×2 = 14 cm (ans)
may it help you
premsingh941148:
Right answer
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Answered by
4
perimeter of rectangle=2(32+12)=
88cm
circumference of circle =
88cm
circumference of circle=2πr
2πr=88cm
2×22/7×r=88cm
r=14cm
88cm
circumference of circle =
88cm
circumference of circle=2πr
2πr=88cm
2×22/7×r=88cm
r=14cm
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