The length and breadth of a room are 10m and 4m respectively. Find the number of square tiles of side 50cm that are required to pave on the floor of the room. Also, find the total cost of the tiles at Rs. 22.50 per tile.
Answers
Answered by
7
Soln:
Rectangle:-
length=10m
Breadth=4m
Area of rectangle=l*b
=10*4
=40m
Square:-
Side=50cm
Area of square=s*s
=50/100*50/100=0.25
No.of tiles required to pave the floor =area of rectangle/area of square
=40/0.25
=4000/25
=160
No.of tiles required is 160
Cost:-
Cost of one tile is =22.50rs
Cost of 160 tiles=160*22.50
= rs 3600
No .of tiles is 160.cost of tiles is rs 3600
kumarianil05:
thax for the answer
Answered by
2
Heya user!!
here is ur answer
length of the room=10m
breadth of the room=4m
area of the ground=L×B
10×4
40m^2
area of one tile=side^2
=50×50
=2500cm^2
=0.25m^2 (1 m^2=10000cm^2)
No of tiles to pave on the floor of the room
=area of floor/area of one tile
=40/0.25
=4000/25
=160 tiles
cost of 1 tile = ₹22.5
cost of 160 tiles = 22.5×160
=₹3600
if it helps u then pls mark it as brainliest
Regards
Divya
^_^
here is ur answer
length of the room=10m
breadth of the room=4m
area of the ground=L×B
10×4
40m^2
area of one tile=side^2
=50×50
=2500cm^2
=0.25m^2 (1 m^2=10000cm^2)
No of tiles to pave on the floor of the room
=area of floor/area of one tile
=40/0.25
=4000/25
=160 tiles
cost of 1 tile = ₹22.5
cost of 160 tiles = 22.5×160
=₹3600
if it helps u then pls mark it as brainliest
Regards
Divya
^_^
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