the length and breadth of park are in ratio 2:1 it's perimeter is 240m a path 2m wide run inside it along its boundary find the cost of paving the path at rs 80per sq.metre
Answers
AnswEr :
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Let the Length be 2x and, Breadth be x.
↦ Perimeter = 2 × (Length + Breadth)
↦ 240 m = 2 × (2x + x)
- Dividing both term by 2
↦ 120 m = (2x + x)
↦ 120 m = 3x
- Dividing both term by 3
↦ x = 40 m
• DIMENSIONS OF OUTER GROUND :
↦ Length = 2x = 2(40) = 80 m
↦ Breadth = x = 40 m
• DIMENSIONS OF INNER GROUND :
↦ Length = 80 - 2(2) = 80 - 4 = 76 m
↦ Breadth = 40 - 2(2) = 40 - 4 = 36 m
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• R E Q U I R E D ⠀A R E A :
⇒ Area Required = Outer Area - Inner Area
⇒ Area Required = (L × B) - (l × b)
⇒ Area Required = (80 × 40) - (76 × 36)
⇒ Area Required = (3200 - 2736) m²
⇒ Area Required = 464 m²
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• C O S T ⠀O F ⠀P A V I N G :
↠ Cost = Area Required × Rate
↠ Cost = 464 m² × Rs. 80
↠ Cost = Rs. 37,120
∴ Cost of Paving of Road is Rs. 37,120
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Answer:
• Length : Breadth = 2 : 1
• Perimeter = 240 m
• Width of path = 2 m [Which is inside the park.]
• Cost of paving the path at 80 per sq.m
Let the length be 2x and the breadth be x