Question

The length and breadth of Park are in Ratio 2 ratio 1 and its perimeter is 240 M a path 2 m Wide run inside it along it boundary find the cost of paving the Parth at rupee 80 per metre square

Answer 1

let length = 2x
then breadth = 1x
perimeter =240m
so, 2 (2x+1x)= 240m
4x+2x=240m
so,6x=240m means x= 240/6=40m
then length = 2×40=80m
breadth = 1×40=40m
area of outer park = 80×40 = 3200sq.m
area of inner park = 80-4×40-4= 76×36
= 2736sq.m
area of path = outer park-inner park
= 3200sq.m - 2736sq.m
=464sq.m
cost of paving the path = 464×80 =Rs.37120

Answer 2

Answer:

Step-by-step explanation:

Let's length = 2x

then breadth=1x

perimeter=240m

so,2(2x+1x)=240m

4x+2x =240m

so,6x =240m means

x=240÷6 =40m

then length=2×40=80

breadth=1×40=40m

Area of outer part=80×40=3200 sq.m

Area of inner park=80-4×40-4=76×36

=2736 sq.m

area of path=outer park-inner park

=3200 sq.m-2736 sq.m

=464 sq.m

cost of paving the path

=464×80

=Rs.37120= Answer