Question

the length and breadth of rectangle are (3a+2b) and (2a-b)respectively .find the perimeter and area of rectangle in the form of algebraic expression.​

Answer 1

length =3a+2b

breadth=2a-b

perimeter=2(l+b)

2((3a+2b)+(2a-b))

2(3a+2b+2a-b)

2(5a+b)

10a+2b.

area=l*b

(3a+2b)*(2a-b)

6a^2+ab-2b^2

Answer 2

Perimeter = 2 ( l + b )

$= 2(3a + 2b + 2a - b) \\ = 2(5a + b) \\ = 10a + 2b$
Area = l × b

$(3a + 2b)(2a - b) \\ 3a(2a - b) + 2b(2a - b) \\ 6a^{2} - 3ab + 4ab - 2b \\ 6a^{2} + ab - 2b$
HOPE IT HELPS YOU !!!!