The length and breadth of rectangular garden are in ratio 7:3. If area of the field is 525m.sq, then find cost of fencing it at Rs.75 per m.
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Let the length be 7x and the breadth be 3x metres.
Area of the field
[tex]= l \times b \\ = 7x \times 3x \\ = 21 x^{2} \ m^{2} [/tex]
[tex]21 x^{2} =525 \\ x^{2} = \frac{525}{21} =25 \\ x= \sqrt{25} =5[/tex]
Length of field
Breadth
Perimeter of field (Length of fence)
Cost of 1 m fence = Rs. 75
Cost of 100 m fence
If it helped you, please mark the answer as the Brainliest. Please!
Area of the field
[tex]= l \times b \\ = 7x \times 3x \\ = 21 x^{2} \ m^{2} [/tex]
[tex]21 x^{2} =525 \\ x^{2} = \frac{525}{21} =25 \\ x= \sqrt{25} =5[/tex]
Length of field
Breadth
Perimeter of field (Length of fence)
Cost of 1 m fence = Rs. 75
Cost of 100 m fence
If it helped you, please mark the answer as the Brainliest. Please!
Answered by
0
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