The length and breadth of the base of a cuboidal pool are 4.5 m and 6 m and its height is 2 m. If tiles are fitted to the base and the four walls of the pool, then what is the total area covered by the tiles?
1️⃣ 96 m²
2️⃣ 54 m²
3️⃣ 69 m²
4️⃣ 42 m²
Answers
Answer:
length = 4.5 m
breath= 6 m
height = 2m
the area covers by tiles= 2h( l+ b) + l×b
2×2(4.5+6) +4.5×6
4(10.5) + 27
42+27
69 m^2
Answer:
The correct answer is option(3) 69m²
Step-by-step explanation:
Given
Length of the cuboidal pool =l = 4.5m
Breadth of the cuboidal pool = b = 6m
Height of the cuboidal pool = h = 2m
To find,
The total area to be tiled
Recall the formula
The total surface area of a cuboid = 2(lb+bh+lh), where l is the length, b is the breadth and h is the height of the cuboid
Solution:
Since the total area to be tiled is base and four walls,
the required area to be calculated = lb+2bh+2lh
Substituting the value of l, b, and h we have
lb+2bh+2lh = 4.5 ×6 + 2×6×2+2×4.5×2
= 27+ 24+18
= 69
∴ The total area to be covered with tiles = 69m²
The correct answer is option(3) 69m²
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