Question

the length and breath of a rectangle are 11 cm and 9 cm . find its area and perimeter??​

Answer 1

Answer:

Area =11*9=99 cm^2

Perimeter=2(11+9)=2*20=40 cm

Answer 2

Correct Question-:

• The length and breadth of a rectangle are 11 cm and 9 cm . Find its area and perimeter ?

AnswEr -:

$\boxed{\blue{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:40 cm}}}}$

$\boxed{\blue{\sf{\star{\:Area \:of\:Rectangle \:is\:99 cm²}}}}$

Explanation-:

Given ,

• The length of Rectangle is 11 cm .
• The breadth of Rectangle is 9 cm .

To Find ,

• The area and perimeter of Rectangle.

☆ Figure related to the question-:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 11 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 9 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Solution-:

• $\boxed{\blue{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:2(length+ breadth)}}}}$

Here ,

• The length of Rectangle is 11 cm .
• The breadth of Rectangle is 9 cm

Now ,

$\pink{\sf{\rightarrow {Perimeter \: of\: Rectangle \:-: 2( 11+ 9 ) }}}$

$\pink{\sf{\rightarrow {Perimeter \: of\: Rectangle \:-: 2( 20 ) }}}$

$\pink{\sf{\rightarrow {Perimeter \: of\: Rectangle \:-: 40 cm }}}$

Therefore,

• $\boxed{\purple{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:40 cm}}}}$

Now ,

• $\boxed{\blue{\sf{\star{\:Area \:of\:Rectangle \:is\:length\times breadth}}}}$

Here ,

• The length of Rectangle is 11 cm .
• The breadth of Rectangle is 9 cm.

Now ,

$\pink{\sf{\rightarrow {Area \: of\: Rectangle \:-: (11 \times9 ) }}}$

$\pink{\sf{\rightarrow {Area \: of\: Rectangle \:-: 99 cm² }}}$

Therefore,

.

• $\boxed{\purple{\sf{\star{\:Area \:of\:Rectangle \:is\:99 cm²}}}}$

Hence ,

• $\boxed{\purple{\sf{\star{\:Perimeter \:of\:Rectangle \:is\:40 cm}}}}$
• $\boxed{\purple{\sf{\star{\:Area \:of\:Rectangle \:is\:99 cm²}}}}$

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