The length and the breadth of a conference hall are in the ratio 8:5 and its perimeter is 234 m. Find the:-
(i) area of the floor of the hall.
(ii) number of tiles, each rectangle of size 20 cm x 15 cm, required for the floor of the hall.
(iii) cost of the tiles at the rate of 1600 per 100 tiles.
please answer with prosedure
Answers
Step-by-step explanation:
By proportional value = x
length= 8x
breadth= 5x
perimeter = 234
234 =2×(l+b)
234 = 2×( 8x+ 5x)
234= 2× ( 13x)
234/2=13x
117 =13x
117/ 13 =x
9 = x
length = 8×9 = 72
breadth = 5× 9= 45
(i)area of rectangle = l×b
= 72 × 45
= 3240 cm^2
(ii) cost= 3240×1600/100
= 51840
Answer:
Here is your answer
Step-by-step explanation:
By proportional value = x
length= 8x
breadth= 5x
perimeter = 234
234 =2×(l+b)
234 = 2×( 8x+ 5x)
234= 2× ( 13x)
234/2=13x
117 =13x
117/ 13 =x
9 = x
length = 8×9 = 72
breadth = 5× 9= 45
(i)area of rectangle = l×b
= 72 × 45
= 3240 cm^2
(ii) cost= 3240×1600/100
= 51840