Math, asked by BeAuTyBLusH, 1 day ago

⌨︎ The length and the breadth of a rectangular field are in the ratio 5 : 3. If its perimeter is 128 m, find the dimensions of the field.

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Answers

Answered by Anonymous
7

Answer:

 \huge \mathcal{ \fcolorbox{aqua}{azure}{ \red{Question}}}

The length and the breadth of a rectangular field are in the ratio 5 : 3. If its perimeter is 128 m, find the dimensions of the field.

 \huge \mathcal{ \fcolorbox{a}{azure}{ \pink{Answer}}}

Length of the rectangular field= 5x

Breadth of the rectangular field = 3x

Perimeter of the rectangular field = 2(5x + 3x)

 = 2 \times 8x

 = 16x

By the condition,

 \huge \mathcal{ \fcolorbox{aqua}{azure}{ \green{16x = 128}}}

 \huge{x =  \frac{128}{16} }

 \huge \mathcal{ \fcolorbox{aqua}{azure}{ \blue{x = 8}}}

Length of the rectangular field= 5 × 8

= 40m

Breadth of the rectangular field = 3 × 8

= 24m

Answered by INDnaman
4

Answer:

Length of the rectangular field= 5x

Breadth of the rectangular field = 3x

Perimeter of the rectangular field = 2(5x + 3x)

= 2 \times 8x=2×8x

= 16x=16x

By the condition,

</p><p>\huge{x = \frac{128}{16} }x= </p><p>16</p><p></p><p>

128

\huge \mathcal{ \fcolorbox{aqua}{azure}{ \blue{x = 8}}} </p><p>

Length of the rectangular field= 5 × 8

= 40m

Breadth of the rectangular field = 3 × 8

= 24m

24M

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