Question

the length and the breadth of a rectangular field is 480 255 find the length of wire required to fencing it also find the cost of fencing @ rupees 7 per metre​

Answer 1

Answer:

10290

Step-by-step explanation:hi pls tell where is the mistake

Answer 2

Answer :

$\underline{\boxed{\mathsf{1470m \: and \: 10,290rs}}}$

Given :

• Length of field = 480m
• Breadth of field = 255m

To find :

• Length of wire required to fencing .
• Cost of wire at 7rs per metre.

Solution :

$\setlength{\unitlength}{2cm}</p><p>\begin{picture}(16,4)</p><p>\thicklines</p><p>\put(8,3){\circle*{0.1}}</p><p>\put(7.8,3){\large{A}}\put(7.4,2){\mathsf{\large{255m}}}</p><p>\put(8,1){\circle*{0.1}}</p><p>\put(7.8,1){\large{B}}\put(9.3,0.8){\mathsf{\large{480m}}}</p><p>\put(11.1,1){\large{C}}</p><p>\put(8,1){\line(1,0){3}}</p><p>\put(11,1,){\circle*{0.1}}</p><p>\put(8,1){\line(0,2){2}}</p><p>\put(11,1){\line(0,3){2}}</p><p>\put(8,3){\line(3,0){3}}</p><p>\put(11,3){\circle*{0.1}}\put(11.1,3){\large{D}}\end{picture}$

PART - 1 (Length of wire)

Now we know that,

$\boxed{\bigstar \: \mathsf{Perimeter \: of \: Rectangle = \: 2(Length \: + \: Breadth)}}$

Therefore ,

$\mathsf{\longrightarrow \: Boundary \: (perimeter) \: = Length \: of \: wire = 2(480m + 255m)}$

$\mathsf{\longrightarrow \: Length \: of \: wire \: required = 2(480m + 255m)}$

$\mathsf{\longrightarrow \: Length \: of \: wire \: required = 2(735m)}$

$\mathsf{\longrightarrow \: 1470m}$

Therefore we have

$\mathsf{\longrightarrow \: Length \: wire \: required\: to fence = \boxed{1470m}}$

$\rule{290}{1}$

PART - 2 (Cost for fencing)

Now we know,

$\mathsf{\longrightarrow \: Length \: of \: Wire = 1470m}$

$\mathsf{\longrightarrow \: Cost \: per\:metre = 7rs}$

Therefore

$\mathsf{\longrightarrow \: Total \: cost \: fencing = 1470m \times 7rs}$

$\mathsf{\longrightarrow \: = 1470m \times 7rs}$

$\mathsf{\longrightarrow \: = 10,290rs}$

Therefore we have

$\mathsf{\longrightarrow \: Total \: Cost \: of \: fencing = \boxed{10,290rs}}$

$\rule{300}{1}$

$\huge \underline{\mathsf{\star \: \blue{More \: to \: know \: }\star }}$

Formula Related To Rectangle

$\mathsf{\longrightarrow \: Area \: of \: Rectangle = Length \times Breadth}$

$\longrightarrow \: \mathsf{Perimeter \: of \: Rectangle = \: 2(Length \: + \: Breadth)}$

Formula Related To Rectangle

$\mathsf{\longrightarrow \: Area \: of \: Square = {(Side)}^{2}}$

$\longrightarrow \: \mathsf{Perimeter \: of \: Square = \: 4(Side)}$

Formula Related To Square

$\mathsf{\longrightarrow \: Area \: of \: Triangle = \dfrac{1}{2} Base \times Height}$

$\longrightarrow \: \mathsf{Perimeter \: of \: Triangle= \: Sum \: of \: all \: Sides}$

$\rule{290}{1}$

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