Question

The length and the breadth of a
rectangular park are 65 m and 45 m,
respectively. Two cross roads, each 5
m wide, run at right angles through the
centre and parallel to its sides. Find the

cost of roads at the rate of rupees 25
per meter square.

Answer 1

Solution:

For a rectangular park :

> Length = 65 m

> Breadth = 45 m

> Two cross roads each of 5m wide run at right angles through the center and parallel to its sides .

To Find : The cost of gravelling the roads

Let us find the area of the roads first .

For the road running parallel to the length :

Area = 5 * [ Length Of Park ]

> 5 * 65 m

> 325 m

For the road running parallel to the breadth :

> 5 * 45 m

> 225 m

Area of both roads :

> A1 + A2 - cross sectional area of overlap

> 325 + 225  - 25

> 525 m^2 .

Now, the roads are graveled @ 25 per m^2 .

Total Cost Of Graveling :

> Rs. 25 x 525

> Rs. 13125

This is the required answer.

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Answer 2

Answer:

Given :-

• Length of park = 65
• Breadth of park = 45 m
• Two cross roads, each 5m wide, run at right angles through thecentre and parallel to its sides

To Find :-

Total cost

SoluTion :-

Firstly the road are running parallel by 5 m

Length :-

$\tt \: Length = 65 \times 5$

$\tt \: Length \: = 325 \: m$

Breadth :-

$\tt \: Breadth = 45 \times 5$

$\tt \: Breadth = 225 \: m$

Area of both sides

$\tt \: 325 + 225 - 25$

$\tt \: 550 - 25$

$\tt \: 525 {m}^{2}$

Now,

Let's find total cost

Total cost = 25 × 525

$\mathfrak \pink{Total cost = 13125}$