The length and the breadth of a rectangular park are in the ratio 5:3 and its perimetre is 128m find the area of the park
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Let the length be 5x and breath be 3x
According to question
perimeter of the rectangle=128m
2 (l+b)=128m
2×8x=128
16x=128
x=8
now length=40m
breath=24m
area of rectanular park =l×b
=40×24m2
=96m2
According to question
perimeter of the rectangle=128m
2 (l+b)=128m
2×8x=128
16x=128
x=8
now length=40m
breath=24m
area of rectanular park =l×b
=40×24m2
=96m2
kunal0912:
Area of Park = 90 m^2 not 96 m^2
sorry 960m^2
oh by mistake i forgot to write 0
It's ok friends
Answered by
0
We are given, Length/Breadth=5/3
Let Length, l= 5x ...................(1)
and,Breadth, b=3x...................(2)
We are also given, Perimeter of Park= 128m
2(l+b)=128m
so, l+b=128/2
l+b=64
By Eqn. (1) & (2)
l+b=5x+3x=64
So, 8x=64
x=64/8
∴ x=8
By Putting x=8 in Eqn. (1) & (2)
l=5x=5*8=40m
and, b=3x=3*8=24m
∴Area of Park=l*b
=40*24
=960 m^2
Let Length, l= 5x ...................(1)
and,Breadth, b=3x...................(2)
We are also given, Perimeter of Park= 128m
2(l+b)=128m
so, l+b=128/2
l+b=64
By Eqn. (1) & (2)
l+b=5x+3x=64
So, 8x=64
x=64/8
∴ x=8
By Putting x=8 in Eqn. (1) & (2)
l=5x=5*8=40m
and, b=3x=3*8=24m
∴Area of Park=l*b
=40*24
=960 m^2
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