The length and the breadth of a rectangular park are in the ratio 8:5.A path 1.5 m wide, running all around the outside of the park has an area of 5 9 4 m square . Find the dimension of park
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Define x:
Given that the ratio of length and breadth = 8 : 5
Let the length of the park be 8x
And the breadth of the park be 5x
Find the area of the park in term of x:
Area = Length x Breadth
Area = (8x) x (5x) = 40x² m²
Find the Length and Breadth of the park and the path:
Length = 8x + 1.5 + 1.5 = ( 8x + 3 ) m²
Breadth = 5x + 1.5 + 1.5 = (5x + 3) m²
Find the area of the park and the path:
Area = Length x Breadth
Area = (8x + 3) (5x + 3) m²
Solve x:
Given that the area of the path is 594 m²
(8x + 3) (5x + 3) - 40x² = 594
40x² + 24x + 15x + 9 - 40x² = 594
39x + 9 = 594
39x = 585
x = 15 m
Find the dimension of the park:
Length = 8x = 8(15) = 120 m
Breadth = 5x = 5(15) = 75 m
Answer: The park is 120 m by 75 m
Given that the ratio of length and breadth = 8 : 5
Let the length of the park be 8x
And the breadth of the park be 5x
Find the area of the park in term of x:
Area = Length x Breadth
Area = (8x) x (5x) = 40x² m²
Find the Length and Breadth of the park and the path:
Length = 8x + 1.5 + 1.5 = ( 8x + 3 ) m²
Breadth = 5x + 1.5 + 1.5 = (5x + 3) m²
Find the area of the park and the path:
Area = Length x Breadth
Area = (8x + 3) (5x + 3) m²
Solve x:
Given that the area of the path is 594 m²
(8x + 3) (5x + 3) - 40x² = 594
40x² + 24x + 15x + 9 - 40x² = 594
39x + 9 = 594
39x = 585
x = 15 m
Find the dimension of the park:
Length = 8x = 8(15) = 120 m
Breadth = 5x = 5(15) = 75 m
Answer: The park is 120 m by 75 m
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